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Mathematics 20 Online
OpenStudy (mackenzie2013):

What is the common ratio in the following geometric sequence? 3, 12, 48, 192, With the formula an = a1 · rn - 1.

OpenStudy (lukebluefive):

The previous problem involved adding a number to get the next term. This one involves multiplying a number to get the next term. Do you see a number that is added to each term to get the next one?

OpenStudy (lukebluefive):

Sorry, multiplied by each term to get the next one.

OpenStudy (mackenzie2013):

So you would take an=3 X ?-1

OpenStudy (lukebluefive):

Yes, you're on the right track.

OpenStudy (lukebluefive):

I think the equation is actually an = a1 x r(n-1), however.

OpenStudy (lukebluefive):

Otherwise it wouldn't match the geometric sequence.

OpenStudy (mackenzie2013):

So An=3 x the common ratio (n-1)

OpenStudy (lukebluefive):

Exactly.

OpenStudy (mackenzie2013):

im confused about the common ratio part... blonde moment lol

OpenStudy (lukebluefive):

Well, just divide each term by the one before it. That will give you the common ratio, which is just a fancy term for what you need to multiply a term in the geometric sequence to get the next term.

OpenStudy (mackenzie2013):

Ahh ok

OpenStudy (mackenzie2013):

So An=3 x 4 (n-1)

OpenStudy (lukebluefive):

Correct, 4 is the common ratio.

OpenStudy (mackenzie2013):

So now we find N?

OpenStudy (lukebluefive):

Well, we weren't given n, and we can't really calculate it. Thankfully, we don't need to. The question only asked for the common ratio of the geometric sequence, which you found.

OpenStudy (mackenzie2013):

So now its just 3x4?

OpenStudy (lukebluefive):

Well, the common ratio is just r. a1 is the first term, which is 3, so what you have there is a1 x r.

OpenStudy (lukebluefive):

I know it's totally confusing, but the answer is simpler than the previous problem would suggest.

OpenStudy (mackenzie2013):

Yeah it is haha

OpenStudy (mackenzie2013):

4?

OpenStudy (lukebluefive):

Yes, that's correct.

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