Question

Medal for solving implicit differentiation problem. question attached

Answer 1

ok, what's your question

Answer 2

the question that is blank

Answer 3

take the derivative of the derivative using implicit differentiation. wherever you get a y'(x) you can substitute in.

Answer 4

I tried that already but the answer was incorrect. Could I cross reference my work with yours to check my calculations?

Answer 5

so to make it a bit easier, first mult both sides by x =>
\[x\cdot y' = -4x-3-y\] now differentiate implicitly.

Answer 6

the left should be \(x\cdot y^{\prime}\)

Answer 7

wtf? this editor is goofy!

Answer 8

\[\Rightarrow x\cdot y''(x) + y'(x) = -4-y'(x) \]\[\Rightarrow y''(x) = \frac{-4-2 y ' (x)}{x} \]

Answer 9

now just sub in for y'(x)