Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

It says to Simplify the expression to lowest terms. 4x^2-9 ------- 2x^2+11x+12 I don't understand how to do this.

OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

@Compassionate

OpenStudy (anonymous):

@wio @skullpatrol

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

hint: factor 4x^2-9 to get (2x-3)(2x+3) we use the difference of squares rule here

jimthompson5910 (jim_thompson5910):

also try to factor 2x^2+11x+12

OpenStudy (anonymous):

Is the bottom (x+4) ? so it would be 2x+3/x+4 @jim_thompson5910

jimthompson5910 (jim_thompson5910):

not quite

jimthompson5910 (jim_thompson5910):

multiply the first coefficient and the last term to get: 2*12 = 24 what two numbers multiply to 24 AND add to 11 (middle coefficient)?

OpenStudy (anonymous):

8 and 3?

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

so 11x = 8x + 3x

jimthompson5910 (jim_thompson5910):

then we factor by grouping

jimthompson5910 (jim_thompson5910):

2x^2+11x+12 2x^2+8x+3x+12 (2x^2+8x)+(3x+12) 2x(x + 4) + (3x+12) 2x(x + 4) + 3(x + 4) (2x + 3)(x + 4)

jimthompson5910 (jim_thompson5910):

So that means 2x^2+11x+12 factors to (2x + 3)(x + 4)

jimthompson5910 (jim_thompson5910):

oh and nvm, i misread

jimthompson5910 (jim_thompson5910):

it looks like you have the right answer

jimthompson5910 (jim_thompson5910):

actually, it should be \[\Large \frac{2x-3}{x+4}\]

jimthompson5910 (jim_thompson5910):

not 2x+3 in the numerator

jimthompson5910 (jim_thompson5910):

since the 2x+3 terms will cancel

OpenStudy (anonymous):

Okay, thanks for the help!

jimthompson5910 (jim_thompson5910):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!