Question

The length of a rectangle is 24 units. Can the perimeter x of the rectangle be 60 units when its width y is 11 units?

Answer 1

Perimeter is W + W + L + L, so enter in your values. Width is 11, length is 24 so; 24 + 24 + 11 + 11 = ?

Answer 2

No, the rectangle cannot have x = 60 and y = 11 because x = 48 + 2y.

No, the rectangle cannot have x = 60 and y = 11 because x = 24 + 2y.

Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 48.

Yes, the rectangle can have x = 60 and y = 11 because x + y is greater than 24. but then it gives me those to pick from

Answer 3

So first, does the equation I showed you work? Remember 2w + 2l, or in this case 48 + 2y = 60 (y = 11)

Answer 4

It doesn't right? So that means you eliminate C. and D.

Answer 5

yeah it doesn't work

Answer 6

So once you have that, you have to find your equation. So, 2w + 2l = P is the equation for perimeter. pretend you don't know the width, then fill in what you know.

Answer 7

2w + 2(24) = 60 right?

Answer 8

yes

Answer 9

so now simplify that for me

Answer 10

2w+48=60

Answer 11

right, so now we just have to rearrange the terms a little bit, so we'll put 48 first, then use y for the width. 48 + 2y = 60

Answer 12

Well, I guess your answer wants x = 48 + 2y. so what answer has that equation?

Answer 13

y is 12?