Question

is x +b = pi/ 4 fin (1+tan x) ( 1+tan b) how would you do this?

Answer 1

* IF

Answer 2

\[\alpha+\beta=\frac{ \pi }{4 }\]
\[\tan \left( \alpha+\beta \right)=\tan \frac{ \pi }{4 }\]
\[\frac{ \tan \alpha+\tan \beta }{ 1-\tan \alpha \tan \beta }=1\]
\[\tan \alpha+\tan \beta=1-\tan \alpha \tan \beta ,\tan \alpha+\tan \beta+\tan \alpha \tan \beta+1=1+1\]
make factors on the left hand side and get the result.