Question

A line passes through the points (8, –1) and (–4, 2).

What is the y-intercept of this line?

Answer 1

well, first off, find its equation \(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
&({\color{red}{ 8}}\quad ,&{\color{blue}{ -1}})\quad &({\color{red}{ -4}}\quad ,&{\color{blue}{ 2}})
\end{array}
\\\quad \\

slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies \cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\

y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form} \)

Answer 2

oh crap haha

Answer 3

after you solve the equation by "y", you'd be left with something like -> \(\bf y=\square x+\square \\
\qquad \qquad \ \uparrow \\
y-intercept
\)

Answer 4

im not to good at this though

Answer 5

well, the exercise is there, for you to be good at it then

Answer 6

The beginning is the most important part of any work.
~~ Plato (370 BC) ~~

Answer 7

thank you

Answer 8

yw