Question

How many boxes will be made from a grid with 3x^6 and 5x^4 columns?
MEDAL REWARDED!!

Answer 1

Any ideas?
No answer choices here.

Answer 2

@jim_thompson5910
@whpalmer4
@preetha

Answer 3

How many columns does the grid have? Are you missing the word "rows" in the problem statement, perhaps?

Answer 4

No

Answer 5

well, a grid only has one number of columns, not two. it also has a number of rows.

Answer 6

I think the answer is talking about 3x^6*5x^4 right?

Answer 7

Since it has something to do with factoring using distributive property?

Answer 8

What are the exponents for then?

Answer 9

that would be my guess, but I'd be happier if the problem was stated in a fashion that made sense. Having two values listed for columns does not.

Answer 10

Oh yea 3x^6 rows you are right

Answer 11

Mislooked :(

Answer 12

the number of rows is \(3x^6\) and the number of columns is \(5x^4\) Multiply those quantities together to get the number of boxes.

Answer 13

15x^10?

Answer 14

Can you help me with another one?

Answer 15

\[3x^6*5x^4 = 3*5*x^{6+4} = 15x^{10}\checkmark\]

Answer 16

Sure, why not?

Answer 17

This one's hard, in my opinion.

Answer 18

What are you supposed to do?

Answer 19

Simplify the following expression

Answer 20

Okay, go through and apply the distributive property to get rid of the parentheses. what do you get?

Answer 21

I am not sure how to do it honestly.

Answer 22

Let's walk through it step by step:

\[5h^4(5+h^2)+h^3(3h^3+6h)-(h^2+4)\]
\[5h^4(5+h^2) = \]

Answer 23

Is it 5h^4(h^2+5)
I am not sure @whpalmer4

Answer 24

Use the distributive property:
\[a(b+c) = a*b + a*c\]

Answer 25

Okay

Answer 26

25h^6?

Answer 27

I am not sure @whpalmer4

Answer 28

Okay, compare the expressions:

\[a(b+c) = a*b + a*c\]\[5h^4(5+h^2) = \]

What is \(a=\)?
What is \(b=\)?
What is \(c=\)?

Answer 29

I don't know how can you multiply 5h^4 by 5?

Answer 30

Or would it be 25h^4+6h^6?
@whpalmer4

Answer 31

\[5h^4*5 = 5*5h^4=25h^4\]

Answer 32

Okay, I was correct , so as the other one?

Answer 33

\[5h^4*h^2 = 5h^{4+2} = 5h^6\]

Answer 34

Oh okay

Answer 35

What do we do next?

Answer 36

So, continue through the expression:
\[h^3(3h^3+6h) =\]

Answer 37

Okay

Answer 38

3h^6+6h^4?
@whpalmer4

Answer 39

Very good. \[-(h^2+4) =\]This is slightly tricky!

Answer 40

How are we suppose to do this?

Answer 41

here's a hint:
\[-(h^2+4) = -1(h^2+4)\]

Answer 42

Oh yeah!

Answer 43

-1h^2+3?

Answer 44

@whpalmer4

Answer 45

where'd that 3 come from?

Answer 46

-1+4?

Answer 47

\[-1(h^2+4)\]\[a(b+c) = a*b + a*c\]want to try again?

Answer 48

Sure

Answer 49

-1h^2-4? I don't know
Sorry, lost connection

Answer 50

\[-1(h^2+4) = -1*h^2 -1*4 = -h^2-4\]

Answer 51

Oh okay, so close

Answer 52

Okay, so now we need to collect all the pieces and stick it together:
\[5h^4(5+h^2)+h^3(3h^3+6h)-(h^2+4) = 25h^4+5h^6+3h^6+6h^4-h^2-4\]
Can you collect any like terms?

You were correct by the way, didn't mean to suggest otherwise!

Answer 53

Then do we just add like terms?

Answer 54

\[-1h^2 = -h^2\]

Answer 55

yes, that's what you do...

Answer 56

Okay

Answer 57

and then write them in order of descending exponents...

Answer 58

:D

Answer 59

Is it 8h^12+31h^10-h^2-4?
@whpalmer4

Answer 60

No, how did you get \(h^{12}\) and \(h^{10}\) from addition where none of the terms had those powers?

Answer 61

I don't know I think I mixed it up somewhere.

Answer 62

So what am I suppose to do then?

Answer 63

you multiplied terms instead of adding them...

\[3x^2+5x^2 = (3+5)x^2 = 8x^2\]

Answer 64

Oh okay

Answer 65

you need to review algebraic manipulation of things with exponents, I think :-)

Answer 66

I was absent on that day

Answer 67

it happens. but you still need to know the material

Answer 68

So is it the same thing just both of the h's are 24?

Answer 69

write out the answer

Answer 70

8h^24+31h^24-h^2-4?

Answer 71

@whpalmer4

Answer 72

How are you getting these enormous exponents?!? You don't change the exponent when adding or subtracting!

Answer 73

Oh really so it's the same thing ......

Answer 74

Look, adding \[3x^2 + 2x^2 = 3*x*x + 2*x*x\]That doesn't give you \[6*x*x*x*x!\]

Answer 75

Okay

Answer 76

it gives you \[(x*x + x*x + x*x) + (x*x+ x*x) = 5*x*x = 5x^2\]

Answer 77

I am just so bad at this unit!

Answer 78

You need to talk to your teacher about getting the material you missed.

Answer 79

I know planning tomorrow

Answer 80

This is absolutely crucial bedrock algebra, and you'll be in deep doo-doo if you don't understand it...

Answer 81

That's why I need your help due to test tomorrow

Answer 82

So we just leave the exponents as usual right?

Answer 83

Or the same thing when it once was?