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OpenStudy (anonymous):
A 2.05L flexible container at a pressure of 1.0 atm is squeezed. What would the new pressure be if it were squeezed to a volume of 0.45L?
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OpenStudy (aaronq):
there are 3 formulas you should be familiar with, this is one of them: \(P_1V_1=P_2V_2\)
OpenStudy (mertsj):
Did you plug into that formula?
OpenStudy (mertsj):
\[2.05(1)=.45(x)\]
OpenStudy (anonymous):
2.05L x 1 atm= P x (0.45L) ?
OpenStudy (anonymous):
then would you divide by 2.05? or by 0.45?
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OpenStudy (mertsj):
|dw:1392863880390:dw|
OpenStudy (mertsj):
|dw:1392863916088:dw|
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