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Chemistry 21 Online
OpenStudy (anonymous):

A 2.05L flexible container at a pressure of 1.0 atm is squeezed. What would the new pressure be if it were squeezed to a volume of 0.45L?

OpenStudy (aaronq):

there are 3 formulas you should be familiar with, this is one of them: \(P_1V_1=P_2V_2\)

OpenStudy (mertsj):

Did you plug into that formula?

OpenStudy (mertsj):

\[2.05(1)=.45(x)\]

OpenStudy (anonymous):

2.05L x 1 atm= P x (0.45L) ?

OpenStudy (anonymous):

then would you divide by 2.05? or by 0.45?

OpenStudy (mertsj):

|dw:1392863880390:dw|

OpenStudy (mertsj):

|dw:1392863916088:dw|

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