Ask your own question, for FREE!
Mathematics 4 Online
OpenStudy (anonymous):

product rule. problem in comments

OpenStudy (anonymous):

\[f(x)= (-3e^x)(4\sqrt{x})\]

OpenStudy (isaiah.feynman):

Use the constant multiple rule on both brackets

OpenStudy (anonymous):

So it would be \[(-3e^x)(\frac{ 2 }{ \sqrt{x} }) ?\]

OpenStudy (nincompoop):

it would be wise if you got rid of the denominator

OpenStudy (nincompoop):

1/sqrt(x) = x^(-1/2)

OpenStudy (anonymous):

\[(-3e^x)(4x^\frac{- 1 }{ 2 })\]

OpenStudy (nincompoop):

right. and constant multiple rule just states that the constants can be multiplied themselves -3*4[e^x * x^(-1/2)]

OpenStudy (nincompoop):

then remember this for product rule f(x) = uv f' = u'v + uv'

OpenStudy (nincompoop):

g(x) = uvw g' = u'vw + uv'w + uvw' h(x) = suvw h' = s'uvw + su'vw + suv'w + suvw' see how it works?

OpenStudy (anonymous):

yes i understand product rule, it's the e^x that is giving me trouble

OpenStudy (isaiah.feynman):

Nah e^x is the friendliest function in calculus.

OpenStudy (anonymous):

Well I've never seen it until now. I'm only in calc I

OpenStudy (isaiah.feynman):

Well, how is it troubling you?

OpenStudy (anonymous):

I've never seen it, so I don't know the properties of it

OpenStudy (anonymous):

\[-12(e^x)(4x^\frac{ -1 }{ 2 })\] that's what I have so from from what he said

OpenStudy (isaiah.feynman):

Use the product rule again on the brackets

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!