Question

I've been stuck on this problem for so long :( Find the double integral by interpreting it as the volume of a solid.

Answer 1

You might want to try some of that Gorilla glue remover. They should sell it at your local walmart. Hope this helped! :D

Answer 2

\[\int\limits_{}^{}\int\limits_{}^{}\sqrt{4-x ^{2}-y ^{2}}\]

Answer 3

\[x ^{2}+y ^{2}\le4\]

Answer 4

and x and y are both greater than or equal to 0 of course

Answer 5

what does sqrt(4 - x^2 - y^2) look like

Answer 6

a paraboloid

Answer 7

no

Answer 8

a circle?

Answer 9

with radius 2?

Answer 10

it's a upper hemisphere

Answer 11

with radius two

Answer 12

okay, so you'd compute the area of the hemisphere using 2 as the radius?

Answer 13

you're supposed to interpret the double integral above using the volume of the hemisphere

Answer 14

which is 2/3pir^2

Answer 15

okay?

Answer 16

Still confused

Answer 17

2/3pi(2)^2?

Answer 18

ans: "the double integral can be interpreted as the volume of the hemisphere whose radius is 2"