So, I was checking my solutions to some problems I was working on and this one was probably the most confusing. (Attachment coming in a bit...if it works)

Question

anonymous · Answer

attachment

anonymous · Answer

If you guys can't open it, that's totally fine.

anonymous · Answer

What math class are you in? It will affect my ans.

anonymous · Answer

This is actually physics 1. Sorry.

anonymous · Answer

what is you highest level of math?

roadjester · Answer

I think what he means is, for this kind of problem, you can approach it using geometry or calculus

anonymous · Answer

Oh, well the highest math class I've taken was a calc 1 class.

roadjester · Answer

that make things easier

anonymous · Answer

Ok so  i understand that you find the velocity by finding the area under the curve, i get that.

anonymous · Answer

HOWEVER! I have no idea why he added the -6m/s there. That just threw me off.

roadjester · Answer

that's initial velocity

roadjester · Answer

you need to add it to your answer

anonymous · Answer

you understand anti derivatives?

anonymous · Answer

yes, but it's been a while since I've done some of those.

roadjester · Answer

ok, so at t=4, you get 8 m/s
subtract 6, the 6 from t=0;
your answer should be 2m/s

anonymous · Answer

and anti derivative of acceleration is volosity

anonymous · Answer

I still don't understand why. It was just asking for velocity at t=0

anonymous · Answer

That should give you the understanding of why it is the area under the line.

anonymous · Answer

I understand that. It's the same as finding position under a velocity curve.

anonymous · Answer

The line is acceleration

roadjester · Answer

it wants t=4; you were given t=0;

roadjester · Answer

$$v_f = v_i+at$$

anonymous · Answer

Ooh...okay. I'm sorry , i guess i missed that. I'm just really nervous i guess. I have an exam tomorrow evening.

anonymous · Answer

i understand it now! Thank you so much!