Question

solve for x
logx+log(x-3)=log(3x)
is the answer x=0?

Answer 1

\(\log(x)+\log(x-3)=\log(x(x-3))\)
so taking both sides to the power of 10 we see
\(x(x-3)=3x\)
solve for x

Answer 2

the options are x=0 x=0,6 x=6 or there are no solutions

Answer 3

sove for x

Answer 4

\(x^2-3x-3x=0\\x^2-6x=0\\x(x-6)=0\\so\\x=0 \ or \ x=6\)but x cant be 0

Answer 5

\[\log_{3x}-\log_{x}=\log_{(x-3)} \]
\[\log_{(3x/x)}=\log_{3}=\log_{(x-3)} \]
\[x-3=3\]
\[x=6\]

Answer 6

\(x^2-3x-3x=0\\x^2-6x=0\\x(x-6)=0\\so\\x=0 \ or \ x=6\)
but x cant be 0, x = 6

Answer 7

oh I see ok I get it now thanks