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Mathematics 15 Online
OpenStudy (anonymous):

maximum problem

ganeshie8 (ganeshie8):

H = x + y

ganeshie8 (ganeshie8):

maximize : xy

ganeshie8 (ganeshie8):

yes, of all the rectangles a square has a maximum area

ganeshie8 (ganeshie8):

but u wanted to prove it using calculus eh ?

OpenStudy (anonymous):

how?

ganeshie8 (ganeshie8):

you need to maximize the function : xy

ganeshie8 (ganeshie8):

get rid of y, by replacing it wid H-x : x(H-x)

ganeshie8 (ganeshie8):

take the first derivative and set it equal to 0. that gives u max/min points

OpenStudy (anonymous):

so its 1-2x

ganeshie8 (ganeshie8):

if u want to avoid calculus : notice that the function is a simple quadratic. so, max value = vertex

ganeshie8 (ganeshie8):

ok, lets do the calculus way :)

OpenStudy (anonymous):

yes yes..

ganeshie8 (ganeshie8):

x(H-x) Hx - x^2 take first derivative : H - 2x set it equal to 0 and solve x

OpenStudy (anonymous):

ow i was wrong.. i thought that's 1.. hehe

OpenStudy (anonymous):

H/2 ad thats it!!! Thank you so much @ganeshie8

ganeshie8 (ganeshie8):

derivative of \(x\) is \(1\) derivative of \(cx\) is \(c\)

ganeshie8 (ganeshie8):

np... u wlc :)

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