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maximum problem
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H = x + y
maximize : xy
yes, of all the rectangles a square has a maximum area
but u wanted to prove it using calculus eh ?
how?
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you need to maximize the function : xy
get rid of y, by replacing it wid H-x : x(H-x)
take the first derivative and set it equal to 0. that gives u max/min points
so its 1-2x
if u want to avoid calculus : notice that the function is a simple quadratic. so, max value = vertex
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ok, lets do the calculus way :)
yes yes..
x(H-x) Hx - x^2 take first derivative : H - 2x set it equal to 0 and solve x
ow i was wrong.. i thought that's 1.. hehe
H/2 ad thats it!!! Thank you so much @ganeshie8
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derivative of \(x\) is \(1\) derivative of \(cx\) is \(c\)
np... u wlc :)
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