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Mathematics 16 Online
OpenStudy (anonymous):

What does "identity" of a function mean?

OpenStudy (timaashorty):

This explains it well ; http://www.wolframalpha.com/input/?i=identity+function

OpenStudy (amistre64):

an identity is like looking in the mirror--you see yourself

OpenStudy (amistre64):

in addition, we have 0 as the identity; since a+0 = a in multiplication, we have a as the identity; since a * 1 = a

OpenStudy (amistre64):

an identity in general is defined as an element that when worked together with some operation, gives us back the same element: f (operate) id = id (operate) f = f

OpenStudy (anonymous):

Okay, now let * be a binary operation on set Q of rational numbers. a*b =ab/4 Does this operation have an identity?

OpenStudy (amistre64):

yes ... a * i = ai/4 = a therefore i/4 =1 when i=4

OpenStudy (anonymous):

what about a*b = a (b)^2

OpenStudy (amistre64):

can you determine an element i, such that a*i = i*a = a ?

OpenStudy (anonymous):

1 ?

OpenStudy (amistre64):

a(i)^2 = 1 ; if 1=1 or -1 i(a)^2 = a ; if i = 1/a since there is no unique identity element for this, it is simply undefined/does not exist

OpenStudy (amistre64):

pfft, a(i)^2 = a that is

OpenStudy (anonymous):

So, because the "i" can be 1 or -1, identity does not exist?

OpenStudy (amistre64):

correct, since i can be: 1, -1, or 1/a there is no unique element, i, that we can claim as THE identity element

OpenStudy (anonymous):

Okay, but i dont get 1/a. a (i)^2=a will mean i^2 =1 right? Where did 1/a come from?

OpenStudy (amistre64):

a * i ::has to equal:: i * a the operation says, x*y is defined to be the first, multiplied by the square of the second. a i^2 ::has to equal:: i a^2 in order for i to exist

OpenStudy (amistre64):

\[i~a^2=a\] \[i=\frac{a}{a^2}\] \[i=\frac{1}{a}\]

OpenStudy (anonymous):

Oh! Right. Now, I get it :)

OpenStudy (anonymous):

I finally get the identity thing :D Thank you so much!! :)

OpenStudy (amistre64):

youre welcome :)

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