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Mathematics 7 Online
OpenStudy (anonymous):

2(x + 7)2 = 64

OpenStudy (anonymous):

what do you need?..

OpenStudy (anonymous):

it solved by the square root property of equality

OpenStudy (***[isuru]***):

\[2(x + 7)^{2} = 64\] u mean this ?

OpenStudy (anonymous):

yes

OpenStudy (***[isuru]***):

first divide the both sides by 2...what will u get ?

OpenStudy (***[isuru]***):

\[\frac{ 2(x+7)^{2} }{ 2 } = \frac{ 64 }{ 2 }\]

OpenStudy (anonymous):

wait multiply or divide?

OpenStudy (anonymous):

oh never mind

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

why divide by 2?

OpenStudy (***[isuru]***):

u cant remove the square sign (^2) while u got the 2 on the same side

OpenStudy (***[isuru]***):

so u have to get rid of the 2

OpenStudy (anonymous):

\[(x+7)^2=32 \] ?

OpenStudy (***[isuru]***):

yep

OpenStudy (***[isuru]***):

now take the square root of both sides..

OpenStudy (anonymous):

okay

OpenStudy (***[isuru]***):

\[\sqrt{(x+7)^{2}} = \pm \sqrt{32}\]

razor99 (razor99):

wow sooo easy

OpenStudy (anonymous):

you lost me'

OpenStudy (***[isuru]***):

now i think u remember these properties\[\sqrt{a} = a^{\frac{ 1 }{ 2 }}\] so.. \[\sqrt{a^{2}} = a^{\frac{ 1 }{ 2 } \times 2}\]

OpenStudy (anonymous):

Sure

OpenStudy (***[isuru]***):

\[\sqrt{(x+7)^{2}} = (x + 7)^{2 \times \frac{ 1 }{ 2 }} = (x + 7)\]

OpenStudy (***[isuru]***):

so... \[( x + 7)= \pm \sqrt{32}\]

OpenStudy (anonymous):

ok

OpenStudy (***[isuru]***):

now u can solve it for x... can u do that ?

OpenStudy (anonymous):

surrrrre

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