Mathematics
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OpenStudy (anonymous):
2(x + 7)2 = 64
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OpenStudy (anonymous):
what do you need?..
OpenStudy (anonymous):
it solved by the square root property of equality
OpenStudy (***[isuru]***):
\[2(x + 7)^{2} = 64\]
u mean this ?
OpenStudy (anonymous):
yes
OpenStudy (***[isuru]***):
first divide the both sides by 2...what will u get ?
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OpenStudy (***[isuru]***):
\[\frac{ 2(x+7)^{2} }{ 2 } = \frac{ 64 }{ 2 }\]
OpenStudy (anonymous):
wait multiply or divide?
OpenStudy (anonymous):
oh never mind
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
why divide by 2?
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OpenStudy (***[isuru]***):
u cant remove the square sign (^2) while u got the 2 on the same side
OpenStudy (***[isuru]***):
so u have to get rid of the 2
OpenStudy (anonymous):
\[(x+7)^2=32 \] ?
OpenStudy (***[isuru]***):
yep
OpenStudy (***[isuru]***):
now take the square root of both sides..
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OpenStudy (anonymous):
okay
OpenStudy (***[isuru]***):
\[\sqrt{(x+7)^{2}} = \pm \sqrt{32}\]
razor99 (razor99):
wow sooo easy
OpenStudy (anonymous):
you lost me'
OpenStudy (***[isuru]***):
now i think u remember these properties\[\sqrt{a} = a^{\frac{ 1 }{ 2 }}\]
so..
\[\sqrt{a^{2}} = a^{\frac{ 1 }{ 2 } \times 2}\]
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OpenStudy (anonymous):
Sure
OpenStudy (***[isuru]***):
\[\sqrt{(x+7)^{2}} = (x + 7)^{2 \times \frac{ 1 }{ 2 }} = (x + 7)\]
OpenStudy (***[isuru]***):
so...
\[( x + 7)= \pm \sqrt{32}\]
OpenStudy (anonymous):
ok
OpenStudy (***[isuru]***):
now u can solve it for x... can u do that ?
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OpenStudy (anonymous):
surrrrre