Predict which of the following would shift the equilibrium to the right in the following reaction C2H2 + H20---> CH3CHO <--- 1)removing H2O (g) from the system 2)adding CH3CHO (g) to the system 3) removing C2H2 (g) from the system 4) adding H2O (g) to the system
if you think of the reaction arrow to be the pivot-point on a balance, when you change something about a system at equilibrium, the balance is "broken". for each of those changes, which one will force the movement from the reactant side to the product side?
removing C2H2 ?
if you remove \(C_2H_2\), then the reactant side now "weighs less" than the product side. Will that make some of the mass move to the right to restore the balance?
no it wont
so what change (stress) will cause the reaction to shift and move some of the mass from the left side to the right side?
you need to make the reactant side "too heavy" or the product side "too light"
adding H2O
that will do it, GJ
Thanks :)
YVW
Join our real-time social learning platform and learn together with your friends!