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Mathematics 11 Online
OpenStudy (anonymous):

@djcool31 @mathmale

OpenStudy (anonymous):

OpenStudy (anonymous):

@mathmale Sorry my computer froze

OpenStudy (***[isuru]***):

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OpenStudy (***[isuru]***):

the length of the base = CB = 2 x BD so all we need to do is find BD \[\tan ( 52) = \frac{ opposite \ side }{ adjacent \ side \ } = \frac{ AB }{ BD }\]\[BD = \frac{ AB }{ \tan 52 } = \frac{ 91 }{1.27 } =71.65 \] now multiply this value by 2 and that is the length of the base.. got it :) ?

OpenStudy (anonymous):

142?

OpenStudy (anonymous):

HELP WITH THIS @mathstudent55

OpenStudy (mathstudent55):

BP = OT

OpenStudy (mathstudent55):

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OpenStudy (mathstudent55):

For the known angle of 33 degrees, the 7000-ft side is the opposite side, and x is the adjacent side. Which trig function relates the opposite to the adjacent sides?

OpenStudy (mathstudent55):

This is a reminder: SOH CAH TOA SOH: sine=opposite/hypotenuse CAH: cosine=adjacent/hypotenuse TOA: tangent=opposite/adjacent

OpenStudy (anonymous):

SOH?

OpenStudy (mathstudent55):

SOH means the sine is the opposite over the hypotenuse I asked which trig function relates the _opposite_ to the _adjacent_?

OpenStudy (anonymous):

Tangent

OpenStudy (mathstudent55):

Right. That means you write: \(\tan 33^o = \dfrac{opp}{adj} \) \(\tan 33^o = \dfrac{7000}{x}\) Now you solve for x. \(\dfrac{\tan 33^o}{1} = \dfrac{7000}{x}\) Cross multiply: \(x \tan 33^o = 7000 \times 1\) Divide both sides by tan 33: \(x = \dfrac{7000}{\tan 33^o}\) Now use a calculator to find x.

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