how to differentiate y=e^(x/a^2)
What is the objective of this question sir?
how to differentiate
use chain rule
just show me it plz
sure :) corrected typo before : \(\large y=e^{x/a^2}\)
check ur notes and confirm if it is \(y\) on the lft side....
no no its x
ohhh sorry it is y
cool :)
\(\large y=e^{x/a^2}\) \(\large \frac{dy}{dx}=\frac{d}{dx}(e^{x/a^2})\)
wats the derivative of e^x ?
lnx
nope. derivative of e^x is just e^x
ln x is the inverse of e^x, its not the derivative ok ?
\(\large y=e^{x/a^2}\) \(\large \frac{dy}{dx}=\frac{d}{dx}(e^{x/a^2})\) \(\large \frac{dy}{dx}=e^{x/a^2} * \frac{d}{dx}(x/a^2)\)
ok
since we dont have just e^x, we need to take derivative of exponent again. its called chain rule.
see if above looks okay :)
yeah but what about d(x/a^2)
good question :) we still need to work it out
\(a\) is just a constant. so pull it out
okay
\(\large y=e^{x/a^2}\) \(\large \frac{dy}{dx}=\frac{d}{dx}(e^{x/a^2})\) \(\large \frac{dy}{dx}=e^{x/a^2} * \frac{d}{dx}(x/a^2)\) \(\large \frac{dy}{dx}=e^{x/a^2} * \frac{1}{a^2}\frac{d}{dx}(x)\)
fine ?
wats the derivative of \(x\) ?
derivative of x is just 1
\(\large y=e^{x/a^2}\) \(\large \frac{dy}{dx}=\frac{d}{dx}(e^{x/a^2})\) \(\large \frac{dy}{dx}=e^{x/a^2} * \frac{d}{dx}(x/a^2)\) \(\large \frac{dy}{dx}=e^{x/a^2} * \frac{1}{a^2}\frac{d}{dx}(x)\) \(\large \frac{dy}{dx}=e^{x/a^2} * \frac{1}{a^2} * 1\) \(\large \frac{dy}{dx}=\frac{e^{x/a^2}}{a^2}\)
okay thank u so much if u have a facebook or eamil to keep in touch
np... u wlc :) pm me ur email... il add u :)
brsa999@hotmail.com
ive copied... delete it here it may be misused by others... lol
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