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OpenStudy (abbie):
A. x= 5/2
B. x=15/7
C. x=10/7
D. x=5/7
OpenStudy (abbie):
@Reaper534 @KamiBug
OpenStudy (lukebluefive):
Looks like the substitution method should work. Try getting "y" on one side by itself by adding terms to or subtracting terms from both sides.
OpenStudy (lukebluefive):
I'll get you started. Take the first equation:
\[-3x+8y =5\]
Add 3x to both sides:
\[8y =5 + 3x\]
Then divide both sides by 8:
\[y =\frac{5 + 3x}{8}\]
Now, plug this value for y into the second equation and solve for x.
OpenStudy (abbie):
which value?
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OpenStudy (abbie):
@agent0smith
OpenStudy (lukebluefive):
Plug (5 + 3x)/8 in where y occurs in the second equation (6x - 2y = 10).
OpenStudy (abbie):
so 10= (5+3x)/8
OpenStudy (abbie):
wouls A be correct?
OpenStudy (agent0smith):
-3x+8y=5
6x-2y=10
easiest way is to to use elimination... multiply the second equation by 4 and add them together
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OpenStudy (abbie):
how do i multiply it?
OpenStudy (agent0smith):
multiply everything by 4
OpenStudy (abbie):
I just guessed because my time was over I put C as an answer :/