PLEASE HELP? find the number of O atoms in 8.4 ✕ 10-3 g CuSO4·5 H2O
Recall that 1 mole has 6.022*10^23 molecules. Now look at hoe many O atoms are in 1 molecule of CuSO4.H2O
sorry for the late reply. ok so there are 5 O atoms? or does the 5 in front of the H carry to the O for the 5H2O?
It does carry.
ok thank you, I never fully understood that. ok so ya 5 atoms. what now ?
Well you have to take into account the O's in the CuSO4 part. CuSO4.5H2O is a whole compound.
so 9 O's
Right. So you have 9 O's in every molecule, and there are 6.022*10^23 molecules in 1 mole of a substance.
ok side note. i get confused when the 6.022 stuff is like 1 mole. please explain? It's stupid I know but I kinda wanna understand what that fully means .
Ah ok. Well it means that in 1 mole of a substance, there are 6.022*10^23 number of molecules in it.
That number is called the Avogadro's constant. http://en.wikipedia.org/wiki/Avogadro_constant
so basically 1 mole equals 6.022*10^23?
Yup. Sorry didn't see your reply last night.
haha no worries.
Can you do it now?
ok so i set it up like 8.4 x 10^-3 x 1 x 9 O ----- mass of CuSO4*5 H2O. is that right?
Wait no. To find the number of moles you divide the mass with the molar volume. And then to find the number of molecules you multiply by the Avogadro's constant. And then to get the number of atoms you multiply by 9.
where do i inset avogadro?
insert*
Join our real-time social learning platform and learn together with your friends!