Question

let f and g be differentiable
f (1)=4, g(1)=3, f ' (3) = -5
f ' (1)= -4, g ' (1)= -3, g ' (3)= 2
If h(x)= f(g(x)), then h ' (1) = ?
a) -9
b) 15
c) 0
d) -5
e) -12

i have no clue how to do this at all, need some help.

Answer 1

h'(1) = f'(g(1)) * g'(1) yes?

Answer 2

can you explain how you got to that?

Answer 3

chain rule
[ f(g(x) ]' = f'(g(x)) g'(x)

and x = 1

Answer 4

ok i understand now thank you