Question

Use the distributive property to multiply.
A. (2y+4)(3y^2+y-4)



Simplify the product using the distributive property
B. (x-2)(x+4)

Answer 1

do you know what to do?

Answer 2

kind of just keep making simple mistakes and now im kinda mad at it ha

Answer 3

just take your time:
2y*3y^2=6y^3
2y*y=2y^2
2y*-4=-8y
4*3y^2=12y^2
4*y=4y
4*-4=-16
6y^3+2y^2-8y+12y^2+4y-16=

6y^3+14y^2-4y-16

Answer 4

so im still lost @~Jane_Doe~

Answer 5

\[(2y+4)(3y^2+y-4)\]applying the distributive property:
\[(2y+4)(3y^2+y-4) = 2y(3y^2+y-4) + 4(3y^2+y-4)\]Is that step clear?

Answer 6

yeah i get it

Answer 7

So now we do that again, as many times as we need to to get rid of all of the ()'s.

\[2y*3y^2 + 2y*y + 2y*(-4) + 4*3y^2 + 4*y + 4*(-4)\]\]What do you get when you wrestle that to the floor?

Answer 8

2^2+10x-4x-40=x^2+6x-40

Answer 9

wait im ways off i used the wrong last number

Answer 10

no equals sign in the middle, either

Answer 11

also, why are you typing x when the problem uses y?

Answer 12

oh ok im a little lost and i dont know why i put x's

Answer 13

Let's go through it step by step:

\[2y*3y^2 + 2y*y + 2y*(-4) + 4*3y^2 + 4*y + 4*(-4)\]
\[2y*3y^2=\]

Answer 14

I got that im at the point before the answer 6y^3+14y^2-4y-16

Answer 15

\[6y^3 + 2y^2 -8y + 12y^2 + 4y -16\]Is that where you are?

Answer 16

yeah that looks correct what do i do next

Answer 17

add all the \(y^3\) terms together, then all the \(y^2\) terms together, then all the \(y\) terms together, and then all the numeric terms, that's called collecting like terms.

Answer 18

Sorry, I have to leave now...