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Geometry 9 Online
OpenStudy (anonymous):

i need help on two open ended questions.....

OpenStudy (anonymous):

find the value of x. round to the nearest tenth. the diagram is not drawn to scale.

OpenStudy (anonymous):

|dw:1392933840460:dw|

OpenStudy (anonymous):

That is a right triangle. So you automatically know that one of the angles is 90 degrees, you're given that another angle is 35 degree's. So that leaves you with the last angle, equaling 55 degrees. So those are the angles, Are you learning the Pythagorean theorem?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Okay, so do you know the Pythagorean Theorem formula? (I can give you the answers, but I guarantee this would be on a test, so I'm trying to get you to actually understand it)

OpenStudy (anonymous):

a^2+b^2=c^2

OpenStudy (anonymous):

Alrighty, so you know one of the legs, which is 12. You plug in 12 for A or B (whichever you want, but I suggest plugging it in for A) So you'll have 12^2 + B^2 = C^2 Although the question may not give you a number for 'x' pretend X is a number and plug X in for B. Now you have 12^2 + X^2 = C^2

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

Now if you solve for 12^2 you'll get 144. So your equation would be 144 + x^2 = C^2 I was taught that whenever you have an X^2 in an equation always put it in the front So x^2 + 144 = C^2 When I solved mine this way, my teacher accepted it.

OpenStudy (anonymous):

ok so how do i find x?

OpenStudy (anonymous):

I was never taught to do anything else, she just told us that whenever you see something like that, put 144 + (square root sign) x^2 = (square root sign) c^2

OpenStudy (anonymous):

hmmm i dont understand how that works

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