A remote controlled toy car accelerates from rest with constant acceleration, a, under the power of its own wheels on a horizontal balcony until it shoots off the edge of the balcony a distance d = 2 m from its starting point as shown in the figure. If the balcony is h = 10 m high, and the horizontal distance from the point it left the balcony to where the car lands on level ground is D = 4 m, what was the initial acceleration, a, of the car (in m/s2)?
Get the time t from the equation for distance fallen, s = 10m = (1/2) g t^2 the horizontal distance from the table is D = v t = 4 m, which gives you v. The acceleration, a, from v=0 to the v you just found is obtained from v^2 = 2 a s, where s = 2 m, the length along the table.
Must leave. Good luck.
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