Prove that \(f: X \rightarrow Y\) is an injection if and only if the equation \(\bar f^{-1}(\bar f)(A)=A\) holds that for all \(A \in P(X)\). Use this to prove that \(f: X \rightarrow Y\) is an injection if and only if \(\bar f^{-1}: P(Y) \rightarrow X\) is a surjective.
P for the powersets... meaning that all A belongs to a Powerset X... hmm oh maybe I should the definition of the inverse on this one... ... the powerset y implies powerset x is a surjective meaning that's it's onto
@Euler271
so f: X -> Y is an injection then that equation holds... so it's a one to one function
@tomhue
what is this o_o i can't help with this
proving a function... I don't know either. xX)(WE*#(@)
which class is this?
introduction to advanced mathematics...but the majority of the topics are discrete math
@zzr0ck3r
Join our real-time social learning platform and learn together with your friends!