Question

30 ml of 0.10M NaOH neutralized 25.0ml of HCI
Determine the concentration of the HCI?

1. Write the balanced chemical equation for the reaction
NaOH + HCI --> NaCI + H20

2. Extract the relevant information from the qustion:
NaOH v= 30mL, M=0.10

HCI v= 25.0 mL, M=?

3. Convert to Liters
NaOH v= 0.03 L, M= 0.10M

HCI v=0.025L, M=?

4. Calculate moles NaOh:
n(NaOH) = M x V = 0.10 moles/L x 0.03L = 3x10^-3 moles

5. From the balanced chemical equation find the mole ratio
NaOH:HCI = 1:1

Answer 1

HELP ON ANY?

Answer 2

6. Use the mole ratio to determine the number of moles of HCl.
7. Calculate concentration of HCl using c=n/V

Answer 3

For the first question use Molarity*Volume=Molarity*Volume

1. Already balanced