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Given the mass of iron nucleus as 55.85u and A(mass number) =56, find the nuclear density.
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You still need help on this question? @Nivi
Yes, I do!
A'ight. Hold on
\[n=\frac{A}{(4/3)\pi R^3}\]
thats the formula for finding the nuclear density
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and as for R you can find it by :
\[R=A^{1/3} * 1.25*10^{-15}\]
Oh right! Then, the volume can be found!
the 1.25 comes from a constant value r but I forgot its significance :3 *yeah. I wrote the formula for finding the volume before the important thing. silly of me
Lol, I get it now! :)
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Thank you ! :)
Haha. Good :)
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