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(log base(a) b) x (log base (b) a)
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it can be log base(a) a = 1
\[\log_{a}{b}*\log_{b}{a} = \frac{\log a \log b}{\log a \log b} = 1\]
thanks it makes sense
Yup, it's the base change formula if I'm not mistaken. log base(a) b = log a / log b.
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