Question

How would i solve this? http://prntscr.com/2udort

Answer 1

@wolfe8

Answer 2

Factor then solve for x?

Answer 3

HMMMMMMMM. Good question.

Answer 4

I think it's when you have the denominator=0 What do you know? I barely remember anything about this. Imma look it up

Answer 5

horizontal asymptotes represent the behavior at very large values of x (both positive and negative)

Answer 6

at large values of \(x\) the first fraction becomes \[\frac{ 3}{4}\]because the \(x^2\) term is dwarfed by the \(x^3\) terms

Answer 7

http://www.freemathhelp.com/finding-horizontal-asymptotes.html

So factor out first yea.

Answer 8

ok thanks

Answer 9

I don't believe it is necessary to factor first, though it may simplify seeing the behavior.

Answer 10

If factoring and canceling changed the value of the fraction, we couldn't do it