How would i solve this? http://prntscr.com/2udort

Question

tester97 · Answer

@wolfe8

tester97 · Answer

Factor then solve for x?

wolfe8 · Answer

HMMMMMMMM. Good question.

wolfe8 · Answer

I think it's when you have the denominator=0 What do you know? I barely remember anything about this. Imma look it up

whpalmer4 · Answer

horizontal asymptotes represent the behavior at very large values of x (both positive and negative)

whpalmer4 · Answer

at large values of $x$ the first fraction becomes $$\frac{ 3}{4}$$because the $x^2$ term is dwarfed by the $x^3$ terms

wolfe8 · Answer

tester97 · Answer

ok thanks

whpalmer4 · Answer

I don't believe it is necessary to factor first, though it may simplify seeing the behavior.

whpalmer4 · Answer

If factoring and canceling changed the value of the fraction, we couldn't do it