Question

Can someone please help i'm stuck on one part!!
h(x)= 5sqrtf(x)^4

Answer 1

What is to be done?

Answer 2

ok I have this so \[1/5(f(x)^4)^{1/5}(f(x)^4)'\]

Answer 3

?? We have \(g(x) = \sqrt[5]{\left[f(x)\right]^{4}}\) and we seek \(g'(x)\)?

Answer 4

we have h(x) =\[\sqrt[5]{f(x)^4}\]

Answer 5

find h'

Answer 6

Oh, sorry. Not sure why I switched to g(x).

Ummm... What, in the name of reason, are you doing?

\(h(x) = \sqrt[5]{\left[f(x)\right]^{4}} = [f(x)]^{4/5}\)

\(h'(x) = \dfrac{4}{5}\left[f(x)\right]^{-1/5}\)

Try to make your life simpler. No need to do anything the hardest way possible.

Answer 7

ok thankyou so much because I was confused :)