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find the distance from (3,7,-5) to each of the following the xy-plane, yz- plane
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The point (3,7,-5) lies in an xy-plane (x,y,-5), which makes it -5 from the xy-plane made at the axis (x,y,0). Likewise, it is 7 from the xz-plane, and 3 from the yz-plane. The distance from the z-axis is simply the distance formula using the x- and y-coordinates: d = sqrt([(3)^2 + (7)^2]) = sqrt(58)
thank you, so if it is just asking for the distance from the x y or z axis, you do the distance formula, but if its asking for the distance from the plane, you simply use the numbers in the original point... it just seemed to easy, I thought there would be more algebra
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