Ask your own question, for FREE!
Chemistry 14 Online
OpenStudy (anonymous):

I need help making some calculations for that cabbage juice titration lab thingy :P

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I think I can do 6 on my own tho

OpenStudy (anonymous):

ok how old r u?

OpenStudy (anonymous):

JW

OpenStudy (anonymous):

i'm 16, sophomore

OpenStudy (anonymous):

wow u look younger lol I was like woa why is she doin this

OpenStudy (anonymous):

Write the balanced equation for the reaction of acetic acid ( ) and sodium bicarbonate ( ). HC2H3O2 + NaHCO3 ===> NaC2H3O2 + H2CO3 What type of reaction(s) took place? acid-base reactions 2. Calculate the number of moles of that were required to neutralize the in the vinegar. 1 mole HC2H3O2 required for 1mole NaHCO3. There is missing information to answer question 3 to 6. 7)HBr is a strong acid, ionizes completely; Mole = (0.250 mol/L )( 0.0264 L) = 0.0066 mol HBr> H+ + Br- 0.250 M . 0.250 M 0.250 M 0.0066 mol .. 0.0066 mol H+ + OH- > H2O 0.0066 mol H+ neutralizes 0.0066 mol OH^- ion CsOH is a strong base and it dissociates completely; CsOH(aq) > Cs^+(aq) + OH^-(aq) 0.0066 mol < 0.0066 mol

OpenStudy (anonymous):

I have no clue what I just said lol

OpenStudy (anonymous):

what'd you do, copy yahoo ?? lol that doesnt apply to my lab :P

OpenStudy (anonymous):

and yeah its an old pic

OpenStudy (anonymous):

ikr I just said some stuff that made me sound smart lol

OpenStudy (anonymous):

im 14 so idk

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

thank you for wasting my time -.-

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!