Question

Find the zeros of the polynomial function.

f(x) = x3 + x2 - 42x

Answer 1

0 would be one, because if you plug 0 in for x, it would all equal 0

Answer 2

so factor x out and then try finding the factors of the function f(x)=x^2+x-42

Answer 3

factorize it...
x^3 + x^2 -42x = x ( x^2 + x - 42 )

= x ( x^2 + 7x - 6x - 42 )

= x [ x ( x + 7) - 6( x + 7) ]

= x [ (x - 6) ( x + 7) ]

Answer 4

f(x) = x(x+7)(x-6)

zeros are: -7, 0, 6

Answer 5

now equal it to zero and solve it for x... and u vill have ur zeros
x [ ( x -6) ( x + 7) ] = 0
which means
x = 0 or x = 6 or x = -7

so.. the zeros r
-7 , 0 , 6