Question

How would I solve for x in the equation: 0.406779661=-.188ln(x)+2.6979?

Answer 1

isolate ln(x), so it should look like:
ln(x) = (.406-2.6979)/-.188
and then to cancel out the natural log, have both sides be the exponent of e

e^ln(x) = e^[(.406-2.6979)/-.188]

so x = e^[(.406-2.6979)/-.188].