Question

Someone to help me with this?
>bellow;

Answer 1

Functions topic;

Answer 2

substitute the given values for x in to the equation

Answer 3

\\[so ~=~\sqrt{(\sqrt{2})^2 + 3}~ (-)^2 \sqrt{(-\sqrt{2})^2 + 3}\]] that simplifies to \[\sqrt{2+3}~ + \sqrt{2+3} \] then it would be a simple math

Answer 4

Actually, the answer should be 4. I've done this way,, look:

Answer 5

@Julio10 I gather you've covered the binomial theorem?

Answer 6

\(\bf f(x)=\sqrt{2x+3},\quad f(\sqrt{2})=\sqrt{2(\sqrt{2})+3},\quad f(-\sqrt{2})=\sqrt{2(-\sqrt{2})+3}
\\ \quad \\ \quad \\\
\begin{array}{llll}
\left[\sqrt{2(\sqrt{2})+3}-\sqrt{2(-\sqrt{2})+3}\right]^2\\
\qquad \uparrow\qquad \qquad \qquad \qquad \uparrow \\
\qquad a\qquad \qquad \qquad \qquad b
\end{array}\implies (a-b)^2=a^2-2ab+b^2\)