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y=1/4tan(6x-4) find second derivative
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is it \[y = \frac{ 1 }{ 4 }\tan(6x-4)\] ?????????
yes
okay we will use chain rule over here \[\frac{ dy }{ dx} = \sec^2 (6x-4)*\frac{ d }{ dx }(6x-4)\]
this is the first derivative did u follow the step?
yes thank you for helping me out
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in the previous step i forgot to put 1/4 \[\frac{ dy }{ dx } = \frac{ 1 }{ 4 }* \sec^2(6x-4) * 6\]
now take the second derivative and show what u got?
18sec^2(6x-4)tan(6x-4)
yeah u r right
thank you for your help
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pleasure
I have other question.:).y^6+x^3=y^2+10x (0,1)
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