Question

4x^2 - 4x - 8
over
2x + 2
............

Answer 1

How can I find what graph would represent this function?

Answer 2

\(\bf \cfrac{4x^2 - 4x - 8 }{2x + 2}\implies \cfrac{4(x^2 - x - 2) }{2(x + 1)}\)

if you were to factor the numerator's grouped terms, what would you get?

Answer 3

\(\bf x^2 - x - 2\implies (x\pm \square )(x\pm \square )?\)

Answer 4

( x - 2) (x + 1) ?

Answer 5

yeap, thus \(\bf \cfrac{4x^2 - 4x - 8 }{2x + 2}\implies \cfrac{4(x^2 - x - 2) }{2(x + 1)}\implies
\cfrac{\cancel{4}(x-2)\cancel{(x+1) }}
{\cancel{2}\cancel{(x + 1)}}\\ \quad \\
\implies 2(x-2)\implies 2x-4\)

Answer 6

Oh I see! How would I put this as a line on a graph now?

Answer 7

well, y = 2x -4

pick a couple of points, graph away, it's just a straight line

simpler way say, y = 0, solve for "x", then x = 0, solve for "y"
the intercepts, then plot away :)

Answer 8

okay. thanks!:)

Answer 9

yw