Question

I have no idea where to start:
solve for x: _3log to the 6th (8-5v) -1 = -7

Answer 1

you mean this?
\[\log_{3} (8-5x)^{6}-1=-7\]

Answer 2

No, the 6 is right after the g at the bottom of the g. I wish i knew how to type it in

Answer 3

then this? \[3\log_{6} (8-5x)-1=-7\]

Answer 4

yes

Answer 5

except it is -3

Answer 6

ok, wait for a minute

Answer 7

thanks for taking time to help

Answer 8

it said to solve for x but there is a v in the equation......does this still work?

Answer 9

i think "v" is "x"

Answer 10

how does the log 6 work? And thanks again

Answer 11

\[\log_{6} \]=>6^2

Answer 12

Thank you:)