Question

Given that f(x) = 2x + 1 and g(x) = the quantity of 3x minus 1, divided by 2 solve for g(f(3)).

5

7

9

10

Answer 1

\[\Large\bf\sf f(\color{orangered}{x})\quad=\quad 2(\color{orangered}{x})+1\]\[\Large\bf\sf f(\color{orangered}{3})\quad=\quad 2(\color{orangered}{3})+1\]

\[\Large\bf\sf g[\color{royalblue}{x}]\quad=\quad \frac{3[\color{royalblue}{x}]-1}{2}\]
\[\Large\bf\sf g[\color{royalblue}{f(3)}]\quad=\quad \frac{3[\color{royalblue}{f(3)}]-1}{2}\]\[\Large\bf\sf g[\color{royalblue}{f(3)}]\quad=\quad \frac{3[\color{royalblue}{2(3)+1}]-1}{2}\]

Answer 2

so 5?

Answer 3

Hmm where is the 5 coming from? :o

Answer 4

5

7

9

10

Answer 5

the choices

Answer 6

Why did you guess 5 though..?
Was it just a random guess?

Answer 7

no i did the math

Answer 8

atleast i believe i did it correctly

Answer 9

Hmm no that doesn't seem correct :o
\[\Large\bf\sf g[\color{royalblue}{f(3)}]\quad=\quad \frac{3[\color{royalblue}{2(3)+1}]-1}{2}\]Simplify the blue stuff before anything else.\[\Large\bf\sf g[\color{royalblue}{f(3)}]\quad=\quad \frac{3[\color{royalblue}{7}]-1}{2}\]

Answer 10

oh ok i see now

Answer 11

it should be 10 then

Answer 12

thank you

Answer 13

good job \c:/