Question

f(x) = -3 e^x + 2 + e^-5 find f'(0)

Answer 1

\[\Large\bf\sf f(x)\quad=\quad-3e^{x}+2+e^{-5}\]Have you tried finding f'(x) yet?

Answer 2

Did I type that correctly? Or is the +2 supposed to be in the exponent also?

Answer 3

-3 e^(x+2) is f'(x)

Answer 4

yeah +2 supposed to be in the exponent too

Answer 5

\[f(x)=-3e ^{x+2}+e ^{-5}=-3e ^{2}e ^{x}+e ^{-5}\]
\[f'(x)=-3e ^{2}e ^{x},put ~x=0~and~get~the~result.\]

Answer 6

thanks, i got it :D

Answer 7

Whenever you come across function notation that tells you to find f(4) (or something), always plug that into X.
F(x)=1x^2+12
F(4)=1(4)^2+12

:)

Answer 8

got chu

Answer 9

bless you.

Answer 10

That was a sneeze right? 0_o

Answer 11

LOL too funny