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find the missing term of each geometric sequence 3,__, 12
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@whpalmer4
There are a number of ways to go about this one. Do you know the formula for the nth term of a geometric sequence?
no well maybe \[An=a \times r^{n-1}\]
@whpalmer4
Okay, so we have \(a_1 = 3\) and \(a_3 = 12\) if \(r\) is the common ratio, then \[a_2 = a1_*r\]\[a_3 = a_2*r = (a_1*r)*r\]
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\[a_3 = a_1*r^2\]\[\frac{12}{3} = r^2\]\[r=\]
r=2
right
so will it be An=3 * 2^2-1???? will that be the equation we use to find the 2nd term
@whpalmer4
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r = 2. so \[a_n = a_1*r^{n-1} = 3*2^{n-1}\]
if we are trying to find the 2nd term then n=2 right
@whpalmer4
i figured it out thank you
so what is the second term?
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6
very good. how about the 10th term? :-)
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