Question

factor by any method
2x^4-21x^2-11

Answer 1

factor
\[2z^4-21z-11\] then replace \(z\) by \(x^2\)

Answer 2

ok then what is next

Answer 3

oh damn i made a typo, should have written
\[2z^2-21z-11\]

Answer 4

You can start by trying to put them into two separate binomials.

@satellite73 , also, please check the reports or view
[ http://openstudy.com/study#/updates/52ec7367e4b0a362a894b4ea ]

Answer 5

let x^2 = b
then what you have that is more recognizable is 2b^2-21b-11
to factor, multiply the coefficient of b^2 by the constant -11 to get -22
what are the factors of -22 such that when you add them you get -21
yes the factors would be -22, +1
so, 2b^2 -22b +1 b -11
regroup and factor
-11(2b +1) +b(2b +1)
(2b +1)(b-11)
remember b= x^2
so (2x^2 + 1)(x^2 + 1)