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OpenStudy (anonymous):

For a solution of H2SO4, determine the van\'t Hoff factor assuming 0% ionization and 100% ionization

OpenStudy (anonymous):

0%

OpenStudy (anonymous):

Im looking for a value of i not a percentage

OpenStudy (anonymous):

If you have 0% dissociation, then you have a van't Hoff factor of 1. You only have 1 molecule floating around, H2SO4 still bound together. If you completely dissociate all the ions, then you have 2H+ and 1 SO4^2-, which gives you a van't Hoff factor of 3.

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