Question

Use implicit differentiation to find the slope of the tangent line to the curve

3 x^2 - 4 xy + 3 y^3 = 4

at the point ( 2,-2 )
how can you solve this?

Answer 1

Solve for y'(x)
\[
9 y(x)^2 y'(x)-4 x y'(x)-4 y(x)+6 x=0
\]

Answer 2

\[
y'(x)=\frac{2 (3 x-2 y(x))}{4 x-9 y(x)^2}
\]

Answer 3

thank you :D

Answer 4

YW