Mathematics
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OpenStudy (shamil98):
The greatest integer, [x], is equal to the largest integer that is smaller than or equal to x. In the domain [0,100],
how many solutions are there to:
\[x^2 - [x]x = 81.25\]
12 years ago
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OpenStudy (the_fizicx99):
the answer is D :)
12 years ago
OpenStudy (shamil98):
fizi stop trolling -.-
12 years ago
OpenStudy (anonymous):
100-81.25
12 years ago
OpenStudy (shamil98):
why though batman
12 years ago
OpenStudy (the_fizicx99):
k :/
12 years ago
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OpenStudy (anonymous):
k thanks bye close
12 years ago
OpenStudy (shamil98):
dumb it down for me and explain
12 years ago
OpenStudy (anonymous):
Well, factoring might help: \[
x(x-\lfloor x\rfloor)=81.25
\]
12 years ago
OpenStudy (anonymous):
legit way ^
12 years ago
OpenStudy (anonymous):
Suppose \(x = \lfloor x\rfloor +a\). We know \(0\leq a < 1\)
12 years ago
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OpenStudy (anonymous):
Also:\[
x-\lfloor x\rfloor = a
\]
12 years ago
OpenStudy (anonymous):
so \[
xa = 81.25
\]
12 years ago
OpenStudy (anonymous):
\[
a = \frac{81.25}{x}\implies 0\leq \frac{81.25}{x}<1
\]
12 years ago
OpenStudy (anonymous):
So \[
81.25 < x\leq 100
\]
12 years ago
OpenStudy (shamil98):
ah, makes sense, ty.
12 years ago
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OpenStudy (anonymous):
Sham get off that website, if you're going to cheat.
12 years ago
OpenStudy (anonymous):
<3
12 years ago
OpenStudy (shamil98):
this is about learning batman shutup
12 years ago
OpenStudy (shamil98):
if i was aiming for just an answer i would'nt have asked for an explanation
12 years ago
OpenStudy (anonymous):
I was joking
12 years ago
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OpenStudy (anonymous):
I wasn't sure what I was doing. I winged it.
12 years ago
OpenStudy (anonymous):
It's pretty much right lol
12 years ago
OpenStudy (shamil98):
worked out in the end xD
12 years ago
OpenStudy (anonymous):
Did you check it?
12 years ago
OpenStudy (anonymous):
Your answer should be 19 sham, ye?
12 years ago
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OpenStudy (anonymous):
My solution is not complete.
12 years ago
OpenStudy (anonymous):
I only really gave a feasible range, but there will be many gaps in it.
12 years ago
OpenStudy (anonymous):
I didn't put restrictions on \(a\) despite the fact that \(a=x-\lfloor x\rfloor\)
12 years ago
OpenStudy (anonymous):
:)
12 years ago
OpenStudy (anonymous):
if we said \(\lfloor x\rfloor =82\) then:\[
a = \frac{81.25}{82}
\]
12 years ago
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OpenStudy (shamil98):
yeah, they wanted the integer solution so i put 19 batman.
12 years ago
OpenStudy (anonymous):
So \(x =82+ 81.25/82\) is perhaps a solution... the reasoning make sense but it's important to verify.
12 years ago
OpenStudy (anonymous):
What? If \(x\) is an integer then \(x^2-x\lfloor x \rfloor = x^2-x^2=0\)
12 years ago
OpenStudy (anonymous):
I would say all solutions are: \[
\left\{\lfloor x\rfloor +\frac{81.25}{\lfloor x\rfloor }\bigg|x\in (81.25,100]\right\}
\]
12 years ago
OpenStudy (anonymous):
Are you guys talking about a different problem?
12 years ago
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OpenStudy (anonymous):
Same
12 years ago
OpenStudy (anonymous):
Why 19?
12 years ago
OpenStudy (anonymous):
One small alteration:\[
\left\{\lfloor x\rfloor +\frac{81.25}{ x }\bigg|x\in (81.25,100]\right\}
\]
12 years ago
OpenStudy (anonymous):
x^2-[x]x=81.25
x-[x]=81.25/x
12 years ago
OpenStudy (anonymous):
Why 19 though?
12 years ago