Could someone double check my answer ? :) (Integration)
correct! good work :)
woohoo! Thank you @hartnn :) Were on integration by parts its tricky O_o
cool! welcome ^_^ once you have practiced few problems on by parts, you'll be able to do it mentally ;)
oo i hope so! I like math but when i don't understand something, I really don't know whats going on with everything else :|
we're here to clear any of your doubts :)
aw thank you. I might need your help checking another problem :/
sure
I got this marked wrong..
know cos 3x formula ?
well what i did what split in so that cos^2(5at)=1-sin^2(5at)
so my integral read: [1-sin^2(5at)]cos(5at)
then u put u= sin 5at ?
yes correct
integral (1/5a) (1-u^2) du (1/5a) ( u - u^3/3) + c (1/5a) (sin 5at - sin^3 5at /3 ) = sin 5at /5a - sin^3 5at/ 15a i guess you just missed the "a"
du = 5a cos 5at dt cos 5at dt = du/(5a)
i dont understand why the "a" would be there? :/
u = sin 5at du = ... ?
5cos(5at) ?
no! the "5a" is the constant so, du = (5a) cos (5at)
du = 5a cos 5at dt
aww man! ok i see that. gosh these variables -_-
so would my answer be the same but with the "a" in the denominator?
yes, in both denominators = sin 5at /5a - sin^3 5at/ 15a
ok lets see if this works *fingers crossed*
IT DID -_- haha omg
congrats! ;)
your the best :) thank you so much
not actually, but welcome ^_^ your smile is too good! :)
:) thank you
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