Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Could someone double check my answer ? :) (Integration)

OpenStudy (anonymous):

hartnn (hartnn):

correct! good work :)

OpenStudy (anonymous):

woohoo! Thank you @hartnn :) Were on integration by parts its tricky O_o

hartnn (hartnn):

cool! welcome ^_^ once you have practiced few problems on by parts, you'll be able to do it mentally ;)

OpenStudy (anonymous):

oo i hope so! I like math but when i don't understand something, I really don't know whats going on with everything else :|

hartnn (hartnn):

we're here to clear any of your doubts :)

OpenStudy (anonymous):

aw thank you. I might need your help checking another problem :/

hartnn (hartnn):

sure

OpenStudy (anonymous):

I got this marked wrong..

hartnn (hartnn):

know cos 3x formula ?

OpenStudy (anonymous):

well what i did what split in so that cos^2(5at)=1-sin^2(5at)

OpenStudy (anonymous):

so my integral read: [1-sin^2(5at)]cos(5at)

hartnn (hartnn):

then u put u= sin 5at ?

OpenStudy (anonymous):

yes correct

hartnn (hartnn):

integral (1/5a) (1-u^2) du (1/5a) ( u - u^3/3) + c (1/5a) (sin 5at - sin^3 5at /3 ) = sin 5at /5a - sin^3 5at/ 15a i guess you just missed the "a"

hartnn (hartnn):

du = 5a cos 5at dt cos 5at dt = du/(5a)

OpenStudy (anonymous):

i dont understand why the "a" would be there? :/

hartnn (hartnn):

u = sin 5at du = ... ?

OpenStudy (anonymous):

5cos(5at) ?

hartnn (hartnn):

no! the "5a" is the constant so, du = (5a) cos (5at)

hartnn (hartnn):

du = 5a cos 5at dt

OpenStudy (anonymous):

aww man! ok i see that. gosh these variables -_-

OpenStudy (anonymous):

so would my answer be the same but with the "a" in the denominator?

hartnn (hartnn):

yes, in both denominators = sin 5at /5a - sin^3 5at/ 15a

OpenStudy (anonymous):

ok lets see if this works *fingers crossed*

OpenStudy (anonymous):

IT DID -_- haha omg

hartnn (hartnn):

congrats! ;)

OpenStudy (anonymous):

your the best :) thank you so much

hartnn (hartnn):

not actually, but welcome ^_^ your smile is too good! :)

OpenStudy (anonymous):

:) thank you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!