A woman exerts a horizontal force of 3 pounds on a box as she pushes it up a ramp that is 1 feet long and inclined at an angle of 30 degrees above the horizontal.

Find the work done on the box.

im gettin 2.59 =[ what am i doing wrong??

Question

A woman exerts a horizontal force of 3 pounds on a box as she pushes it up a ramp that is 1 feet long and inclined at an angle of 30 degrees above the horizontal.

Find the work done on the box.

im gettin 2.59 =[ what am i doing wrong??

mica · Answer

im using |a||b|costheta

anonymous · Answer

Is there any friction?

anonymous · Answer

and is the 3 pounds the net force, or is that in addition to the down-slope component of the weight force of the box?

anonymous · Answer

work done is physics o_o
its force times distance moved

then you times costheta

so it goes FxDxcosθ

anonymous · Answer

also, convert pounds to newtons 
and while you're at it, feet to metres if needed.

mica · Answer

im not sure how its suppose to really look like 

i did do (3)(1)cos30 but i still got the wrong answer and the final answer is suppose to be in ft-lb

anonymous · Answer

what is the correct answer?

mica · Answer

theres no correct answer given

mica · Answer

|dw:1393051652069:dw| this is how i imagine it

anonymous · Answer

then how do you know that your answer is wrong? ._.

mica · Answer

cuz when i type in the answer it says incorrect