Question

(1+cos(theta))(1/sin(theta)-1/tan(theta)=sin(theta)

Answer 1

u mean
\[[ (1 + \cos \theta ) \times \frac{ 1 }{ \sin \theta } ] - \frac{ 1 }{ \tan \theta } = \sin \theta \] ??

Answer 2

or
\[[ 1 + \cos \theta ] [ ( \frac{ 1 }{ \sin \theta } - \frac{ 1 }{ \tan \theta } ) ] = \sin \theta\]
i think it should be this one

Answer 3

yes this one

Answer 4

first step write
\[\frac{ 1 }{ \tan \theta }\] using sin and cos ... what will u get ?

Answer 5

\[\tan \theta = \frac{ \sin \theta }{ \cos \theta }\]
sooo....
\[\frac{ 1 }{ \tan \theta } = ? \]

Answer 6

[1+cosθ][(1/sinθ−1/tanθ)]=sinθ
[1 + cosθ] [1/sinθ -cosθ/sinθ]
[1 + cosθ][1-cosθ/sinθ]
1 -cos^2 θ/sinθ
sin^2 θ/sinθ
sinθ