Question

The angle of elevation of a jet fighter from a point A on the ground is 60°. After a
flight of 10 seconds, the angle of elevation changes to 30°. If the jet is flying at a
speed of 432 km/hour, find the constant height at which the jet is flying.

Answer 1

use \[\sqrt{3}=1.732\]

Answer 2

my naswer which i know is wrong is coming 249.08 km

Answer 3

@ganeshie8

Answer 4

@uri

Answer 5

@Ashleyisakitty

Answer 6

ok... so the plane is flying 432 m/h

so in 10 seconds it flies 432/(60*6) = 1.2 miles

now draw a picture...



triangle BAJ is isosceles

so JA = AB

so you now have a right triangle



so you can use the sin ratio to find the height

son(60) = h/1.2

hope it helps...