Finding y using the quadratic equation, y+16=225/y

Question

lieutenantgeneral · Answer

y = 209
209 + 16 = 225

anonymous · Answer

No, no.. I have to arrange it like to this $$(y+16)/1-(225/y)=0$$ and then use $$x=(-b±√(b^2-4ac))/2a$$ , to find the solution(s) for y

lieutenantgeneral · Answer

OK.

anonymous · Answer

... yeah, how do i do that? how do I simplify it to insert it in that equation ?

anonymous · Answer

$$
 y+16=\frac {225}y \
y^2 + 16 y =225\
y^2 + 16 y - 225 =0
$$
Use now the quadratics formula

campbell_st · Answer

why not multiply every term by y

and you get 

$$y^2 + 16y = 225$$

now you have a quadratic that you can solve

or 

$$y^2 + 16x -225 = 0$$

anonymous · Answer

Actually this factors
to
$$
(-9 + y) (25 + y)
$$

anonymous · Answer

=0

anonymous · Answer

y=9
y=-25

anonymous · Answer

oh... that seemed easy. lol 
So i just had to multiply y on both sides? thanks both @eliassaab and @campbell_st