Question

Finding y using the quadratic equation, y+16=225/y

Answer 1

y = 209
209 + 16 = 225

Answer 2

No, no.. I have to arrange it like to this \[(y+16)/1-(225/y)=0\] and then use \[x=(-b±√(b^2-4ac))/2a\] , to find the solution(s) for y

Answer 3

OK.

Answer 4

... yeah, how do i do that? how do I simplify it to insert it in that equation ?

Answer 5

\[
y+16=\frac {225}y \\
y^2 + 16 y =225\\
y^2 + 16 y - 225 =0
\]
Use now the quadratics formula

Answer 6

why not multiply every term by y

and you get

\[y^2 + 16y = 225\]

now you have a quadratic that you can solve

or

\[y^2 + 16x -225 = 0\]

Answer 7

Actually this factors
to
\[
(-9 + y) (25 + y)
\]

Answer 8

=0

Answer 9

y=9
y=-25

Answer 10

oh... that seemed easy. lol
So i just had to multiply y on both sides? thanks both @eliassaab and @campbell_st